Mathemafia — The Calculator (Lounge) ~ Replacements Available!

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RandomYoshi

Sweden? More like Memeden.
Chat Operator
Retired Wiki Staff
Hey guys, everyone's favourite mathematical constant here, Pi! After playing some games, I've decided to host a Mafia game of my own, with the theme being mathematics. The roles are going to be mathematical functions and related definitions. Don't fret, you don't have to be good at mathematics to participate!

Rules

  • If you are dead, you are allowed one informationless "bah" post. You must then remain silent about the game until the endgame resolution.
    [*]You can roleclaim, but you cannot quote your role PM.
    [*]In case of a tie, a No Lynch will be in place.
    [*]Mafia kill every Night unless otherwise stated.
    [*]No cheating.
    [*]Voting is done by typing [nobbc]Vote: Player[/nobbc] (which appears as Vote: Player), with "player" being the one who you are voting. Unvotes are done by typing [nobbc]Unvote[/nobbc], which appears as Unvote, do not need to be done, but it would be preferred if they were done before placing a new Vote. Additionally, if you type [nobbc]Unvote: Player Who You Were Voting[/nobbc], which appears as Unvote: Player Who You Were Voting, that would make my life as a host incredibly easier.
    [*]Forward all game-related PMs to me. This means that, if you send a game-related PM to anyone, please include me as a recipient. Additionally, if you have queried somebody on IRC and had a conversation about this game, it would be nice if I could get the complete and unedited logs from any of those conversations.
    [*]You are free to create any game-related QuickTopics, just alert me of the existence of these topics and give me a link to them, and do not lock them before I say so.
    [*]If you are inactive for 200 hours, then you will be modkilled and replaced.
    [*]Each Day phase will last for 4 real-life days; each Night phase will last for 2 real-life days.
    [*]Each Day phase can be requested to be extended twice. The first time it is extended, it will be extended for 2 real-life days. The second time it is requested to be extended, it will be extended for 1 real-life day.
    [*]You must NOT edit your posts. It is unfair if you did something scummy and edit that out. If there's something you wish to point out or add, just post again but don't make it too spammy.
    [*]Orange is my colour. Any attempts at using this colour will be seen as a violation against the rules.


Note that text in blue is not necessary to follow.

I want at least 20 sign-ups, but more would be awesome if I got more than that. Also keep in mind that the maximum amount of players I am accepting is thirty.

Sign-ups

  • Epic Nitwit (Hiyoko Saionji)
  • PoLilynomial (Lily) (Lilith)
  • Reversinator (Time Turner)
  • NSY
  • Smasher (Meowth)
  • Ralph
  • Lakituthequick
  • Hobbes (Tucayo)
  • 23*52*7 (MrConcreteDonkey) (Saul Slendamann)
  • QuizmoManiac (Jayce)
  • Neptune (The End)
  • Nabber (Gundam Tanaka)
  • Yoshiquaker (Yoshiwaker)
  • f(x)=x3+x2+(cos2(x))/2+C (Baby Mario Bloops) (Xerneas)
  • Perfect Number (Pyro) (Keyzer)
  • New Super Mario
  • Blocky (Hajime Hinata)
  • 8-berry (Shoey) (Filthy Rich)
  • Smg2daisy
  • Cirdec
  • 2a quadruple-factorial (Super Mario Bros.)
  • Crackin5*71 (Crackin355)
  • M215 (MarioMaster15) (Beat)
  • Timmy (Yoshi123)
  • Paky (Packy) (A New World Record) [Signed up through IRC]
  • FireEevee (Sylveon)
  • Crash (Tharja) [Signed up through IRC]
  • SM (SonicMario) (Northern Verve)
  • Rocker 26 (Rocker64) (Ino Yamanaka)
  • marioman1213 (Roserade)

Replacement Players

Confirmed receiving role.

Banned Users
|
User
|
Offence
|
Banned From
|
|Pokémon Trainer Red
[td]|[/td][td]Revealing his role after being replaced and ruining the entire plan for his replacement player.[/td][td]|[/td][td]This Game[/td][td]|[/td]



As a finishing note, this game will only be put on the queue after I have finished every role.
 

Bop1996

Power Star
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

limme->this thread response(me) = YES
 

NSY

Celestial Guide
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

in, that's if I'm not banned from playing
 

Smasher

Smasher
Forum Moderator
Chat Operator
Core 'Shroom Staff
Awards Committee
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

math is BORING
 

Bop1996

Power Star
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

no, it equals 2i√2
 

RandomYoshi

Sweden? More like Memeden.
Chat Operator
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

God damn it Bop, I was just going to point that out.

STOP NINJAING THE HOST GOD DAMN IT.
 

RandomYoshi

Sweden? More like Memeden.
Chat Operator
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

Santa Lakitu said:
Enobarbus said:
no, it equals 2i√2
wat

No, you can't get the square root of something smaller then zero.
Yes, you can. The square root of -1 is i, for example. In your case, 65-73=-8=-1*8. So if you take the square root of that, you'd get 2i√2.
 

Vera Misham

Ace Artist
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

Smasher said:
math is BORING
I don't mind math, although I can't really understand stuff like:
RandomYoshi said:
The square root of -1 is i, for example. In your case, 65-73=-8=-1*8. So if you take the square root of that, you'd get 2i√2.
^this.
 

Lakituthequick

Art by BBQ Turtle
Core 'Shroom Staff
Awards Committee
Poll Committee
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

RandomYoshi said:
Santa Lakitu said:
Enobarbus said:
no, it equals 2i√2
wat

No, you can't get the square root of something smaller then zero.
Yes, you can. The square root of -1 is i, for example. In your case, 65-73=-8=-1*8. So if you take the square root of that, you'd get 2i√2.
Well

My Casio says Math ERROR, so I don't know where you've got that from.
 

Bop1996

Power Star
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

his imagination
 

RandomYoshi

Sweden? More like Memeden.
Chat Operator
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

LET ME EXPLAIN THAT BETTER THEN.

First we have a rule that says that √(ab)=√(a)√(b). In our case, a=-1 and b=8. If we apply the formula, we obtain √(-1*8 )=√-1*√8. That is the same thing as saying i√8. Now, 8=2*2*2, so i√8=i√(2*2*2)=i√4√2=2i√2.
 

Ernest Fine

Dreamboat
Chat Operator
Core 'Shroom Staff
Retired Forum Mod
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

this will be fun
 

Yoshi K

Come with me if you want cookies
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

The cube root of negative 1 is -1
 

Lakituthequick

Art by BBQ Turtle
Core 'Shroom Staff
Awards Committee
Poll Committee
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

RandomYoshi said:
LET ME EXPLAIN THAT BETTER THEN.

First we have a rule that says that √(ab)=√(a)√(b). In our case, a=-1 and b=8. If we apply the formula, we obtain √(-1*8 )=√-1*√8. That is the same thing as saying i√8. Now, 8=2*2*2, so i√8=i√(2*2*2)=i√4√2=2i√2.
What if I just say I don't believe you unless you give a legit source.


Santagast the Merry said:
Also, NOO PAGE
wat
 

Bop1996

Power Star
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

you're being ridiculous

http://en.wikipedia.org/wiki/Imaginary_number

also how would we be able to do cool trigonometry things like complex roots or things like that without i

you're making me imagine a world without i, and it's making me very sad
 

RandomYoshi

Sweden? More like Memeden.
Chat Operator
Retired Wiki Staff
Re: Mathemafia — The Calculator (Sign-ups, Lounge)

Santa Lakitu said:
RandomYoshi said:
LET ME EXPLAIN THAT BETTER THEN.

First we have a rule that says that √(ab)=√(a)√(b). In our case, a=-1 and b=8. If we apply the formula, we obtain √(-1*8 )=√-1*√8. That is the same thing as saying i√8. Now, 8=2*2*2, so i√8=i√(2*2*2)=i√4√2=2i√2.
What if I just say I don't believe you unless you give a legit source.
I could prove the formula if that's what you want, which I will do.
First, write √(ab)=(ab)^(1/2). Then apply that (cd)^f=c^f*d^f, obtain (ab)^(1/2)=a^(1/2)*b^(1/2). Now, write a^(1/2)*b^(1/2)=(√a)(√b)=√(a)√(b).

Therefore, √(ab)=√(a)√(b).
Q.E.D.

Enobarbus said:
you're being ridiculous

http://en.wikipedia.org/wiki/Imaginary_number

also how would we be able to do cool trigonometry things like complex roots or things like that without i

you're making me imagine a world without i, and it's making me very sad
ℂ∉{world} ⇒ Bop is sad.
 
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