.999999999... = 1?

do you think .999999... equals 1?

  • yes

    Votes: 24 72.7%

  • no

    Votes: 9 27.3%
  • Total voters
    33
No. Unless of course you put in limitations like "round to x number" and then it would be 1.
 
for all intents and purposes, it is equal to one

if you'd like to turn this into a discussion on empricism vs rationalism then i'd be happy to oblidge
 
0.3.. + 0.3.. + 0.3.. = 0.9.. = 1/3 + 1/3 + 1/3 = 1

http://en.wikipedia.org/wiki/0.999...

So yes
 
the people who say yes have their points
only one naysayer as of now but didn't give a reason

personally I say yes cause of this:
1/3(.333...) + 2/3(.666...) = 3/3(.999...) = 1
 
yes for the reason mentioned above

man i'm slow
 
In my country I use a "," instead of a "." to separate the decimal values.

My formula bases on this one

gif.latex
 
Not necessarily

Mathematically, yeah, it rounds off to be one

However, in stuff like reaching the speed of light, .99999999-% the speed of light is still not the speed of light
 
This is starting to drive me, the math geek (though not as much as Cirdec was a moment ago) crazy.

If .999... and 1 were the same, only one would exist.

However, since there are both of them, they mathematically cannot be one and the same.

Even if 1/3 + 2/3 = 1 and .333... + .66*... = .999..., doing a problem such as the one I am placing below gives different answers.

1 + 1/3 * 6 + 2/3 * 7

Try it!
 
Megamario15 said:
This is starting to drive me, the math geek (though not as much as Cirdec was a moment ago) crazy.

If .999... and 1 were the same, only one would exist.

However, since there are both of them, they mathematically cannot be one and the same.

Even if 1/3 + 2/3 = 1 and .333... + .66*... = .999..., doing a problem such as the one I am placing below gives different answers.

1 + 1/3 * 6 + 2/3 * 7

Try it!
Click to expand...

I don't see your point.
0,999... and 1 are equal, 0,999.... is a limit, something infinite to write. The more nine you have, the closer it is to 1, when you push to the infinite, it has to be equal to 1, because the difference will be pushed to 0.
 
Cirdec said:
Megamario15 said:
This is starting to drive me, the math geek (though not as much as Cirdec was a moment ago) crazy.

If .999... and 1 were the same, only one would exist.

However, since there are both of them, they mathematically cannot be one and the same.

Even if 1/3 + 2/3 = 1 and .333... + .66*... = .999..., doing a problem such as the one I am placing below gives different answers.

1 + 1/3 * 6 + 2/3 * 7

Try it!
Click to expand...

I don't see your point.
0,999... and 1 are equal, 0,999.... is a limit, something infinite to write. The more nine you have, the closer it is to 1, when you push to the infinite, it has to be equal to 1, because the difference will be pushed to 0.
Click to expand...
You won't see my point unless you try it.
Also, the difference between the two amounts can't be found because of the infinite 9s. However, for as many 9s as there are, there are as many 0s followed by a single 1. Now what you're saying is that .000...1 and 0 are equal. (.000...1 is what I just mentioned)
 
To get 0,1 you divide 1 by 10. To get 0,01 you divide 0,1 by 10 so it's 1 divided by 100. By the same process, if 0,9...9 has n number 9, then 1-0,9...9=1/(10n).

Now the thing is, the greater n is, the smaller 1/(10n) is. You introduce the definition of a limit, which gives the result when n will be close to the infinite, so this limit will be equal to 0. Hence 0,99....=1

You have to understand that 0,99.... is not the decimal writing of a number, that's a limit, that's why it is equal to 1.
 
Megamario15 said:
If .999... and 1 were the same, only one would exist.

However, since there are both of them, they mathematically cannot be one and the same.
Click to expand...
1 and (0.5 * 2) both exist and are mathematically one and the same.

I don't follow.
 
1/3 = .333..
2/3 = .666..

1/3 + 2/3 = 3/3 = 1

.333.. + .666.. = .999.. = 1

mm15 I think you're just confusing yourself and/or being to strict with decimals and rounding
 
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